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2026-04-07 [20:27] |
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2026-04-07 [20:23] |

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2026-04-07 |
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X^3 + bx^2 + cx + d = f(x), f'(x) = 3x^2 + 2bx + c, 3/8 -(1/2)b + c = -1/4.... (b-2c)/2 = 5/8, b=2c+(5/4)
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2026-04-07 |
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2026-04-07 |
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f(1/4)=3/8 + (1/2)b + c<0 À̴ϱî..... 3/8 + c+ 5/8 + c<0, 1+2c<0, 2c < -1, c<-1/2
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2026-04-07 |
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f(8) =512+64b+8c+d .... = 512+128c+80+8c+d=592+136c+d ¾Æ´Ï´©°¡Ç®¾îÁÙ»ç¶÷
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2026-04-07 [20:23] |
